Friday, September 15, 2017

The next prime is 3..............1 over 1 - 1/3......................is 1/2/3...............as in one over 2/3.............multiplying both top and the bottom by 3...........as in 3/3...............which is just one.................u get 3/2.............why?.......1 * 3 = 3...............2/3 * 3 = 2.......................3 is 3/1..................2/3 * 3/1 = 2..........the 3's cancel out............u end up with 3/2......................

5 is the next prime...................one the bottom is would be 1 - 1/5............which would leave u with 4/5...................1 over 4/5.....................is 5/4............................is the glass half empty or half full? Both...........if it is half empty............it must be half filled with something....................water, sand, oil, etc............or how would it be half empty, if the other side was not half full?  Or conversely........if u filled a glass, urn......whatever half way.............the other part that is empty would be half.............so if u filled something 1/5 of the way..................4/5 would be left empty...........



Euler's Product Formula

Here is an amazing formula due to Euler:

SUMn=1 to infinity n-s = PRODp prime (1 - p-s)-1 .

What's interesting about this formula is that it relates an expression involving all the positive integers to one involving just primes! And you can use it to prove there must be infinitely many primes. For, if there were only finitely many primes, then the right side of the expression is a finite product, and in particular for s=1. But for s=1, the left side of the equation is the harmonic series which we know must diverge! This is a contradiction, so there must be infinitely many primes.
Presentation Suggestions:
Interested students may wish to take a few terms on the right hand side, use a power expansion, and multiply them out... to get an idea of why the equality holds.
The Math Behind the Fact:
The left hand side, when s is viewed as a complex variable, is also known as the Riemann zeta function. Because of the above relationship, the study of zeta functions is closely related to the study of the

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