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That gives him 365 possible birthdays out of 365 days, so the probability of the first person having the "right" birthday is 365/365, or 100%. The chance that the second person has the same birthday is 1/365. To find the probability that both people have this birthday, we have to multiply their separate probabilities.

Math Forum: Ask Dr. Math FAQ: The Birthday Problem

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Birthday probability problem | Probability and combinatorics | Khan ...

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Well, it could be born on any day that person one was not born on. So there are 364 possibilities out 365. So if ...

Birthday problem - Wikipedia, the free encyclopedia

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Jump to Calculating the probability - The problem is to compute the approximate probability that in a group of n people, at least two have the same birthday. For simplicity, disregard variations in the distribution, such as leap years, twins, seasonal or weekday variations, and assume that the 365 possible birthdays are equally likely.

‎Calculating the probability · ‎Abstract proof · ‎Approximations · ‎An upper bound

Understanding the Birthday Paradox – BetterExplained

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Apr 26, 2007 - The birthday paradox is strange, counter-intuitive, and completely true. ... chance of a problem scenario from 1 we are left with the probability of ...

Math Forum: Ask Dr. Math FAQ: The Birthday Problem

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Suppose you flip a coin and bet that it will come up tails. Since you are equally likely to get heads or tails, the probability of tails is 50%. This means that if you try ...